An A.P consists of 60 terms .If the first and last terms be 7 and 125 find the 31st term
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Answer:
67
Step-by-step explanation:
a = 7
n = 60
an = 125
a31 = ?
an = a + (n-1)d
125 = 7 + (60-1)d
125 -7 = 59d
118 = 59d
118/59 = d
2 = d
an = a + (n-1)d
a31 = 7 + (31-1)2
a31 = 7 + 30*2
a31 = 7 + 60
a31 = 67
hence, the 31st term is 67
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