Question

An A.P. consists of 60 terms. If the first and the last terms be 7 and 125 respectively, find the 32nd term.

Answer 1

Answer:

The 32nd term of an A.P is 69 .

Step-by-step explanation:

Given :  

Number of terms ,n = 60, first term , a =7, last term , a60 (l) = 125

a60 = 125

a + (60 - 1)d = 125

[an = a + (n - 1)d]

7 + 59d = 125

59d = 125 - 7

59d = 118

d = 118/59

d = 2 ……………(1)

 

32nd term :  

a32 = a + (32 - 1)d

a32 = a + 31d

a32 = 7 + 31(2)

[From eq 1]

a32 = 7 + 62

a32 = 69

Hence, 32nd term of an A.P is 69 .

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Answer 2

Answer : 69

Step-by-step explanation:

Given that :

→First term (a) = 7

→last term (l) =125

→Number of terms (n) = 60

Using the formula for nth term ,

[An = a + ( n - 1 ) d]

125 = 7 + ( 60 - 1 )d

125 - 7 = 59d

118 = 59d

•°• d = 118/59

✔Common Difference (d) = 2

Now we have ,

A32 = a + 31d

= 7 + 31 × 2

= 7 + 62

= 69

⚫The 32th term of the Arithmetic Progression is 69.

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