An A.P. consists of 60 terms. If the first and the last terms be 7 and 125 respectively, what will be its 34th term?
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Step-by-step explanation:
a = 7 ,d=? a60= 125
an = a+(n-1)×d
a60=7+(60-1)×d
125=7+(59)×d
125-7=59×d
118=59×d
d= 118/59=2
now,
a34= 7+(33-1)×2
=7+66
=73
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