Question

An.A.P consits of 57 term of which 7th term is 13 and tne last term is 108. Find the 45th term of this



a.P.

Answer 1

SOLUTION:-+

ARITHMETICAL PROGRESSION

A + 6 D = 13

LAST TERM = 108

A+(N-1)D = 108

A+56 D = 108

A+ 6D + 50 D = 108

13 + 50D = 108

50 D= 95

D = 95/50

D =1.7

A + 10.2 = 13

A= 2.8

NOW 45TH TERM IS = A + 46 D

55.2 + 2.8

58 IS THE ANSWER!!!

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