Question

An AC mechanic is using a gas cylinder during the repair of the AC. The cylinder he is using is a iron hollow cylinder of internal and external radii 18 cm and 22 cm respectively and height 14 cm. 1 cm³ of the cylindrical metal weighs 5 gm.

Answer 1

Step-by-step explanation:

Given, Radius of cylindrical container =6cm

Height of cylindrical container =15cm

Volume of cylinder =πr

2

h

=π×36×15

=540πcm

3

Now, as it has to be divided among 10 children

∴ Dividing volume by 10=

10

540

=54πcm

3

Volume of cone + Volume of hemispherical top = Volume of ice-cream in it.

⇒

3

1

πr

2

h+

3

2

πr

3

=πr

2

h

⇒

3

1

πr

2

(4r)+

3

2

πr

3

=54π

⇒

3

1

πr

3

(4+2)=54π

⇒2r

3

=54⇒r=3

Hence, the radius of icecream cone =3 cm.

Answer 2

Answer:

The weight is $35.2kg$.

Step-by-step explanation:

We are given that an AC mechanic is using a gas cylinder during the repair of the AC. The cylinder he is using is a iron hollow cylinder of internal and external radii $18 cm$ and $22 cm$ respectively and height $14 cm$.

The volume is the capacity of the cylinder.

The formula is π$r^{2}h$

Using values, we get π$(22^{2}-18^{2} )14$

π$(484-324)14$

π$160*14$

Using π as$22/7$

Volume is $\frac{22}{7} *160*14=7040cm^{3}$

It is given that $1cm^{3} =5g$

So, $7040cm^{3} =7040*5=35200gm=35.2kg$

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