an ac source of 220v and 50hz is connected with an inductor and a resistor of 10ohm in series if current in circuit is 6A and the average power consumed is 800W find the power factor and value of inductance
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Answer:
The frequency of AC source =f=50Hz
Thus the impedance of the inductor, X
L =ωL=(2πf)L=20πΩ
Resistance of the resistor =20Ω
Thus, the net impedance of the circuit =
X L2 +R 2 =65.94Ω
Thus, the current in the circuit = XV = 65.94Ω
220V =3.33A
Explanation:
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Answer:
220×10×6
_________
800×10
Answer is 1.65
Explanation:
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