Question

an ac source of emf 5v is connected series to rlc circuit at a phase angle 33 degree find potential difference accreoos. capacitor when the magnetude of potential difference accross inductor reaches maximum value of 6​

Answer 1

Answer:

gsiiztiyoyoyhlckyccul

Answer 2

Answer:

A phasor diagram very much like below figure, leads to the condition:

VL−VC=(6.00V)sin(300)=3.00V.

With the magnitude of the capacitor voltage at  5.00V, this gives a inductor voltage magnitude equal to  8.00V. Since the capacitor and inductor voltage phasors are  180°  out of phase, the potential difference across the inductor is  −8.00V.