Question

An ac supply gives 30 V r.m.s. which passes through a 10Ω resistance. The power dissipated in it is(a) 90 √2 W(b) 90 W(c) 45 √2 W(d) 45 W

Answer 1

⭐⭐⭐hey mate!!⭐⭐⭐

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Your answer is option (b) 90watt

<P inst> = Vrms^2/R

<p inst> = 30×30/10

= 90watt

Hope it helps:)

#phoenix

Answer 2

Given that,

RMS voltage, $V=30\ V$

Resistance, R = 10 ohms

To find,

The power dissipated in the resistance.

Solution,

The power dissipated in terms of rms voltage is given by :

$P=\dfrac{V_{rms}^2}{R}\\\\P=\dfrac{(30)^2}{10}\\\\P=90\ W$

So, the power dissipated in it is 90 watts.

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