An ac supply gives 30v rms when it connected to the 10 ohm resistance the power dissipated in it is
shivi14151:
p=v^2/R
Answers
Answered by
3
power =V²/R
= 30×30/10
=90J
I hope you understand
Answered by
2
Given:-
potential difference=30v
Resistance=10ohm
p=vi
=v×v/r
=30×30/10
=30×3
=90 Joules
Advance Happy Holi
✨✨✨✨✨
potential difference=30v
Resistance=10ohm
p=vi
=v×v/r
=30×30/10
=30×3
=90 Joules
Advance Happy Holi
✨✨✨✨✨
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