Question

An ac supply gives 30v rms when it connected to the 10 ohm resistance the power dissipated in it is

Answer 1

power =V²/R

= 30×30/10

=90J

I hope you understand

Answer 2

Given:-

potential difference=30v

Resistance=10ohm

p=vi

=v×v/r

=30×30/10

=30×3

=90 Joules

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