An AC voltage is applied to a resistance R and an inductor L in series, if R and the inductive reactance are both equal to 3 ohm, the phase difference between the applied
voltage and the current in the circuit is
a) π/4
(b) π/2
(c) zero
(d) π/6
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Answer:
fhghvh sorry it went by mistake
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ϕ=tan−1(RXL)
=tan−1(33)
=tan−1(1)
=4πrad
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