Math, asked by futyjk632, 11 months ago

An accident occurred in an industrial institution, 100 people were injured! The number of injured persons with eyes, hands and feet is 30, 50 and 70! In the injured, there are 44 such people (in their eyes and hands) or in (hands and feet) or (legs and hands) injuries! Tell us how many such people in the wounded, whose hands, legs and eyes are all in their hands!

Answers

Answered by Swarnimkumar22
12
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An accident occurred in an industrial institution, 100 people were injured! The number of injured persons with eyes, hands and feet is 30, 50 and 70! In the injured, there are 44 such people (in their eyes and hands) or in (hands and feet) or (legs and hands) injuries! Tell us how many such people in the wounded, whose hands, legs and eyes are all in their hands!

\bold{\underline{Answer-}}

Suppose the number of wounded in the three eyes is x

The number of wounded in two eyes is p, q and r

E = set of wounds in the eye

A = set of wounded in hand

L = set of wounds in the legs

So by Wayne Diagram -

30 - (p+q+x)+50 - (p+x+r) + 70 - (q+x+r)+p+q+r+x = 100

P + q + r + 2x = 50

P + q + r = 44

2x = 6

X = 3
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Answered by Anonymous
4

The number of wounded in two eyes is p, q and r

E = set of wounds in the eye

A = set of wounded in hand

L = set of wounds in the legs

So by Wayne Diagram -

30 - (p+q+x)+50 - (p+x+r) + 70 - (q+x+r)+p+q+r+x = 100

P + q + r + 2x = 50

P + q + r = 44

2x = 6

X = 3

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