Question

An acid solution of 0.005M has a pH of 5. The degree of ionisation of acid

is​

Answer 1

Answer:

Solution

5×10−35×10-3

2×10−32×10-3

5×10−25×10-2

2×10−22×10-2

Answer :

B

Solution :

α=[H+]C=10−55×10−3α=[H+]C=10-55×10-3

=2×10−3

Explanation:

Make me as Brilliant