An acorn falls from the branch of a tree to the ground 25 feet below. The distance, S, that the acorn is from the ground as it falls is represented by the equation S(t) = –16t2 + 25, where t is the number of seconds. For which interval of time is the acorn moving through the air
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for 5/4 secs it remains in air
Step-by-step explanation:
S(t) = –16t² + 25
at t = 0
S(0) = 0 + 25 = 25 feet
it is 25 feet above the ground at 0 time
it will be in air until Distance from ground become 0
let say at t = x distance become zero
=> S(x) = - 16x² + 25 = 0
=> 16x² = 25
=> x² = 25/16
=> x² = 5²/4²
=> x = 5/4
After 5/4 secs it teaches ground
hence for 5/4 secs it remains in air
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