An acoustic signal is reflected off a surface that is 80% absorptive. What is the dB drop in the reflected signal? (dB)
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Answer:
sorry I don't know if know I definitely answer
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Answer:
6.98dB drop
Explanation:
80% absorptive, so % change -80%
dB = 10log(1-(%change/100))
dB = 10log(1-(-80/100))
dB = 6.98
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