Question

an Acroplane taking off from a field has a run of 500. What is acceleration if It leaves the ground in 10 second from the start ?also find the take off velocity.​

Answer 1

Given that, the aeroplane had to run 500 m before taking off. It took off in 10 seconds from the start.

Assuming the acceleration to be constant,

Using second equation of motion, we have

• u = 0 m/s ( Plane was at rest )
• t = 10 s
• s = 500 m

⇒ s = ut + 1/2 at²

⇒ 500 = 0×10 + 1/2 × a × 10²

⇒ 500 = 100a / 2

⇒ 500 = 50a

⇒ a = 500/50

⇒ a = 10 m/s²

Now that we have,

• u = 0 m/s
• t = 10 s
• a = 10 m/s²

Using first equation of motion, take off (final velocity) can be calculated as,

⇒ v = u + at

⇒ v = 0 + 10×10

⇒ v = 100 m/s

Hence,

• Acceleration = 10 m/s²
• Take off velocity = 100 m/s

Answer 2

Answer:

$\huge\underbrace\mathscr\color{lime}{ ⚝Question:–}$

• An aeroplane taking off from a field has a run of 500 m.

• What is the acceleration and take off velocity if it leaves the ground 10 seconds after the start ?

$\huge\underbrace\mathscr\color{lime}{ ⚝Solution:–}$

In the above Question , the following information is given -

• The length of the runway is 500 m.

The aeroplane leaves the ground 10 seconds after the start.

So,

• The speed of the aeroplane while on the ground

➳ ( 500 m / 10 s ) = 50 m/s.

Now, Let us find the acceleration of the

plane.

• ☾❁According to the Second Equation Of Motion

S= ut + (1/2) at^2.

• The plane is innitially at rest.

So, u = 0

➳ 500 = (1/2) x 100

➳ Acceleration = 10 m/s.