Question

an acute angle made by a side of a parallelogram with other pair of parallel sides is 30 degree if the distance between these parallel side is 10cm then the other side is?​

Answer 1

Answer:

GivenABCDisaparallelogram.

AB∥DCandAD∥BC.

∠DAB=60°,

distancebetweentwoparallelsidesABandDC(h)=6

3

cm

In \: \triangle ADM, \angle {AMD} = 90\degreeIn△ADM,∠AMD=90°

Sin 60\degree = \frac{MD}{AD}Sin60°=

AD

MD

\implies \frac{\sqrt{3}}{2} = \frac{6\sqrt{3}}{AD}⟹

2

3

=

AD

6

3

\implies AD = 6\sqrt{3}\times \frac{2}{\sqrt{3}}⟹AD=6

3

×

3

2

\implies AD = 6 \times 2 = 12 \:cm⟹AD=6×2=12cm

Therefore.,

\red{ Required \: length \:of \:the \:side }\green {= 12 \:cm }Requiredlengthoftheside=12cm

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