An acute triangle has side lengths 21 cm, x cm, and 2x cm. If 21 is one of the shorter sides of the triangle, what is the greatest possible length of the longest side, rounded to the nearest tenth?
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Since 21 is one of the shorter sides, it follows that 2x MUST be the longest side
We then get: 2x < x + 21
2x - x < 21
x < 21
Therefore, the longest side, or 2x < 42
Since the longest side, or 2x < 42, then the longest side's length can either be 18.8 cm (choice A), or 24.2 cm (choice B),
but since one of the shorter sides is 21, the longer side will be greater than 21....=24.2
HOPE IT HELPS
MARK AS BRAINLIEST
We then get: 2x < x + 21
2x - x < 21
x < 21
Therefore, the longest side, or 2x < 42
Since the longest side, or 2x < 42, then the longest side's length can either be 18.8 cm (choice A), or 24.2 cm (choice B),
but since one of the shorter sides is 21, the longer side will be greater than 21....=24.2
HOPE IT HELPS
MARK AS BRAINLIEST
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