Question

an adult an a minor boys standing on the ground are two meters apart. The height of the adult is 4 times the height of minor boy..If at the mid point of the line segment joining their feet the angles of elevation of their tops are complementary then find the height of the minor boy..

Answer 1

let the height of minor boy be x
so height of adult is 4x
distance between them is 2m
at the mid point of distance between them the angles of elevation of adult and minor boy are complementary
let the angle of elevation of adult be β
angle of elevation of minor boy is 90-β
now tanβ = 4x/1→1
        tan(90-β) = x/1
          cotβ = x
          1/tanβ = x
           tanβ = 1/x→2
from 1 and 2, we get
             4x = 1/x
             4x² = 1
              x² = 1/4
              x = 1/2 = 0.5m
therefore height of minor boy is 0.5m

Answer 2

Step-by-step explanation:

step by step 1 m changes to 100cm them divides into 2 triangles with 50 - 50 cm

hope its clear