An adulterated sample of milk has a density of
1032kg−m^-3
,
while pure milk has a density of
1080kg−m^−3
.
The volume of pure milk in a sample of 10 L of adulterated milk is
mkvgr1:
I got the purity percent as 97%, am I in the right direction?
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1m³=1000L
1000L contains = 1032 kg milk
10 L contains =1032/1000 x 10
=10.32 kg
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