Question

An advertisement board is 9m long and 6 m broad there are 1.5 mlong lights alog all side of it find the number of lights required to decorate the board hint number of light = perimeter of rectangle ÷ length of 1 light​

Answer 1

Answer:

number of lights required to decorate the board = 20

Step-by-step explanation:

An advertisement board

L = 9m long

B = 6 m broad

perimeter of board= 2(L+B)

= 2(9+6)

= 2(15)

= 30 m

length of one light = 1.5 m= 15/10 m

number of lights required to decorate the board = perimeter of rectangle ÷ length of 1 light

= 30/(15/10)

= 30×10/15

= 2×10

= 20

number of lights required to decorate the board = 20