An advertisement board is 9m long and 6 m broad there are 1.5 mlong lights alog all side of it find the number of lights required to decorate the board hint number of light = perimeter of rectangle ÷ length of 1 light
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Answer:
number of lights required to decorate the board = 20
Step-by-step explanation:
An advertisement board
L = 9m long
B = 6 m broad
perimeter of board= 2(L+B)
= 2(9+6)
= 2(15)
= 30 m
length of one light = 1.5 m= 15/10 m
number of lights required to decorate the board = perimeter of rectangle ÷ length of 1 light
= 30/(15/10)
= 30×10/15
= 2×10
= 20
number of lights required to decorate the board = 20
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