Question

. An advertisement board is in the form of a isosceles triangle with its sides equal to 12 m, 10 m and 10 m, then
the cost of painting it at ₹ 2.25 per m2 is

Answer 1

Answer:

Step-by-step explanation:the total cost is Rs. 1050.

Step-by-step explanation:

Step-by-step explanation: AS given in the question and shown in the attached figure, ΔABC is an advertisement board, which is isosceles with AB = AC.

Also, AB = AC = 13 m  and perimeter is given by

P = AB+ BC+ CA=13+BC+13

36=26+BC

BC=10

Let us draw AD perpendicular to BC, so D will be the mid-point of BC, since ΔABC is isosceles.

Therefore, BD = CD = 5 m

So, from right-angled triangle ABD, we have, after using Pythagoras theorem -

AB^2 =AD^2+ BD^2

Hence, area of ΔABC is given by

A=*1/2*AD*BC=1/2*12*10=60m^2

Now, cost of painting 1 m² = Rs. 17.50

∴ Cost of painting 60 m² = Rs. (17.50 × 60) = Rs. 1050.

Answer 2

Answer:

108 rupees is the total cost of painting per 48 square meters