Question

an advertisement board is in the form of an equilateral triangle of parameter 240 cm find the area of the board using heron's formula used under root 3 equal to​

Answer 1

Answer:

$14400\sqrt{3} cm^2$

Step-by-step explanation:

Side length (a) = 240 cm

Semiperimeter (s) = (240 + 240 + 240)/2 = 360

Δ = $\sqrt{s(s-a)(s-b)(s-c)} \\=\sqrt{s(s-a)^3}\\=\sqrt{360(360-240)^3}\\=\sqrt{360(120)^3}\\=\sqrt{3(120)^4}\\=120^2\sqrt{3}\\=14400\sqrt{3} cm^2$