Question

an advertisement board of an equalitral traingle of perimeter 120 cm. find the area of the board. use √3= 1.73​

Answer 1

Answer:

Given,

perimeter of equilateral∆ = 120 cm.

so it's one side = perimeter/3 = 120/3 = 40 cm.

area of the board = (√3 × 40 × 40)/4

=( 1.73× 40×40)/4

=(173×40×40)/(4×100)

=173×4 = 692 cm2

Answer 2

Hope this helps .............