Question

An advertising executive is studying television viewing habits of married men and women
during prime time hours. Based on the past viewing records he has determined that during
prime time wives are watching television 60% of the time. It has also been determined that
when the wife is watching television, 40% of the time the husband is also watching. When
the wife is not watching the television, 30% of the time husband is watching the television.
Find the probability that (i) the husband is watching the television during the prime time
of television (ii) if the husband is watching the television, the wife is also watching the
television​

Answer 1

Answer:

Step-by-step explanation:

There can be two interpretation of data

1.

wives are watching television 60% of the time

when the wife is watching television, 40% of the time the husband is also watching = (40/100) * 60 = 24 %

When the wife is not watching the television, 30% of the time the husband is watching the  television = (30/100) * (100 - 60) = 12%

the husband is watching the television during the  prime time of television = 24 + 12 = 36%  probability = 0.36

if the husband is watching the television, the  wife is also watching the television​ = 24/(12 + 24) = 24/36 = 2/3

2.

wives are watching television 60% of the time

when the wife is watching television, 40% of the time the husband is also watching

When the wife is not watching the television, 30% of the time the husband is watching the  television

the husband is watching the television during the  prime time of television = 40 + 30 = 70%  probability = 0.7

if the husband is watching the television, the  wife is also watching the television​ = 40/(40 + 30) = 40/70 = 4/7