Question

An aero plane takes off at angle of 30degree to the horizontal.If the componant of its velocity along the horizental is 250 km/h , what is the actual velocity ?Find also the vertical component of the velocity.

Answer 1

$\tan \alpha = \frac{v(y)}{v(x)}$
$\tan(30) = \frac{v(y)}{250kmph}$
$v(y) = \frac{250}{ \sqrt{3} }$
NOW,

$actual \: velocity = \sqrt{ {v(x)}^{2} + {v(y)}^{2} }$
$actual \: velocity = \sqrt{62500 +20833.33 }$
$actual \: velocity = 288.6 \: mps$
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