Question

An aeronautics engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s2. The take off speed for this plane will be 65 m/s. Assuming this minimum acceleration, what is the minimum allowed length for the runway?

Answer 1

Explanation:

S is the length of the runway.

initial velocity = 0 = u

final velocity = 65 m/s = v

minimum acceleration = a = 3 m/sec²

v = u + a t  =>  t = v/a = 65/3 sec

s = u t + 1/2 a t² = 1/2 * 3 * 65²/3² = 704.6 meters

    

if the acceleration is more than 3 m/sec,  then s = v² / (2a)    will be shorter

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