an aeroplain 3000m high passes vertically above another plain at an instant when the angle of two aeropalain from the same point on the ground are 60 and 45 respectivly find the vertical distance between the two plains
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Using tan45°,h=x,when we take the height of one aeroplane be h and the distance of the point from h is x
Now,tan60°=h+3000 /x,3/2x=h+3000,now,put h at place of x.now,3/2h=h+3000,3/2h-h=3000,h(3/2-1)=3000,answer is h=3000/3/2-1
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