an aeroplan is flying horizontlly with a velocity of 600 km/h and at a point A on the ground a bomb is released from it. the bomb strikes the ground at point b the distance AB is?
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Ux = 600x1000/3600 = 500/3 m/s
Velocity of the bomb during the flight is constant due to inertia. Therefore,
Initial velocity in vertical direction, Uy = 0
Height = 1960 m
Step 2:
Find time ‘t’ using the equation [s = ut + 1/2at^2]
Replace distance ‘s’ by height ‘h’ and acceleration ‘a’ by gravity ‘g’
h = 1/2gt^2
t = √(2h)/g = √(2x 1960/9.8) = 20 sec.
Step 3:
Find the distance traversed by the bomb in horizontal direction:
Distance AB = vx t
= 500/3 x 20
= 10/3 x 10^3m
= 3.333 km.
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