An aeroplan taxies on runway of 20s with an acceleration of 4.6m per second before taking of how much distance would it have coverd runway
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Explanation:
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Answer:
The aeroplane would have covered 640 m distance.
Explanation:
a = 4.6 m/s²
t = 20 s
u = 0 m/s
s = ut + ½ at²
=> s = 0 * 20 + ½ * 4.6 * 20²
=> s = 0 + ½ * 4.6 * 400
=> s = ½ * 400 * 4.6
=> s = 200 * 3.2
=> s = 640 m
The aeroplane would have covered 640 m distance.
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