An aeropland taking off from a field has a run of 50m.what is the acceleration and take off velocity if it leaves the ground 10 sec after the start
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Answer:
a= 1 m/s^2
Step-by-step explanation:
We know that,
d = v°t + 1/2 at^2
d in this case is 50 m and t is 10 sec.
initial velocity is v° which will be zero. (assumption)
Hence solving it will give us a which is 1 m/s^2
Now,
V= v° + at
Hence, V @ 10 sec = 0 + 1*10 = 10m/s.
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FYI, plane will never take off at such low speed.
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