Question

An aeroplane accelerates down a runaway at 3 m/s for 30 s until it finally lifts off the ground. Determine the
distance travelled before take off.​

Answer 1

$speed = 3 \frac{m}{s}$

$time \: taken \: = 30s$

$distance \: = \: speed \: \times \: time$

$disatnce \: = 30 \times 3$

$distance \: = 90m$

the aeroplane travel 90 m before take off

Answer 2

Answer: 1350m

Explanation: here u = 0 m/s

a = 3m/(s^2). & t = 30s

so on applying the equation,

S = ut + [(at^2)/2].

and substituting the required value you will get the answer.

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