An aeroplane after completing journey lands on the airstrip at a velocity of 100 m/s. After 40 second it stops. How much distance it will cover during this time?
Answers
Answered by
0
Answer:
400 m
Explanation:
distance= speed x time
therefore distance = 100 x 4
= 400 m
Answered by
0
Answer:
The first one is wrong.
because velocity is given, not speed.
Explanation:
initial velocity=u=100m/s
Time=t=40s
Final velocity=v=0m/s
Distance=s=?
Finding acceleration:-
2.5 m/s²
According to S= UT + ½ at²
s= -600 m
Distance always positive
s= 600 m
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