An aeroplane after landing to the run-way with a speed of 36 Km/h travels in straight line for 5 s and comes to rest. 1. Calculate the deceleration of the aeroplane 2. Calculate the distance travelled by the aeroplane through the run-way.
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Answered by
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Distance travels by plane is 75 meters.
Explanation:
Given
Initial velocity=Vi = 36km/hr = 10 m/s
Time taken =t = 5 sec
Final velocity =Vf= 0
Acceleration =a= - 2m/s^2
Find distance = S=??
As we know
2nd equation of motion
S = Vit + 1/2 (at^2)
S = 10×5 + 1/2 (2×5^2)
S = 50 + 1/2 ( 50)
S = 50 + 25
S= 75 meters
Distance covered by plane is 75 meters.
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Answer:
using division find weather or not the first polynomial is a factor of the second 1. 2x-3;6x²+x²-19x+6 2. x-6;x²-12x+40
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