Question

An aeroplane bus flying with a speed of 500 km/hr. the velocity of the exaust gases relative to the plane is 1500 km/hr find the velocity of the exaust gases relative to an observer on the ground​

Answer 1

Answer:

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Answer 2

Answer:

Relative velocity

V

A/B

=v

A

−v

B

given

V

A/B

=1500Km/h

v

A

−v

B

=1500

v

A

−(−500)=1500

Since the velocity of combustion products and plane are in opposite directions

V

A

=1000km/h