An aeroplane bus flying with a speed of 500 km/hr. the velocity of the exaust gases relative to the plane is 1500 km/hr find the velocity of the exaust gases relative to an observer on the ground
Answers
Answered by
1
Answer:
hope it helps you ✌☺️
Attachments:
Answered by
0
Answer:
Relative velocity
V
A/B
=v
A
−v
B
given
V
A/B
=1500Km/h
v
A
−v
B
=1500
v
A
−(−500)=1500
Since the velocity of combustion products and plane are in opposite directions
V
A
=1000km/h
Similar questions
Math,
1 month ago
Computer Science,
1 month ago
Science,
1 month ago
Chinese,
3 months ago
Social Sciences,
3 months ago
Computer Science,
9 months ago
Physics,
9 months ago
Music,
9 months ago