an aeroplane covers a certain distance in 1hr and 6 min with an average speed of 475km/hr . what will be its average speed if it has to cover the same distance in 45 minutes?
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Answer:
Step-by-step explanation:
v = 475 km/hr
t = 1hr 6min
= 1 6/60 hr = 11/10 hr
v = distance / time
distance = speed * time
= 475*11/10
= 522.5 km
New time = 45 min = 3/4 hr
v = distance / time
= 696.6 km/hr
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