An aeroplane flies 1680 km witha head wind in 3.5 hours. on return trip with same wind blowing, the plane takes 3 hours. Find the plane's air speed and the wind speed.
Answers
Answered by
180
Let the air speed be x km/hr and speed of the wind be y km/hr.
Given, x - y = 1680/3.5
= 480 ---------- (1)
Given, x + y = 1680/3
= 560 ------------ (2)
On solving (1) and (2) we get
x - y = 480
x + y = 560
------------------------
2x = 1040
x = 520.
Substitute x = 520 in above equations, we get y = 40.
Plane's airspeed = 520km/hr and wid speed = 40km/hr.
Hope this helps!
Given, x - y = 1680/3.5
= 480 ---------- (1)
Given, x + y = 1680/3
= 560 ------------ (2)
On solving (1) and (2) we get
x - y = 480
x + y = 560
------------------------
2x = 1040
x = 520.
Substitute x = 520 in above equations, we get y = 40.
Plane's airspeed = 520km/hr and wid speed = 40km/hr.
Hope this helps!
STARK7:
Thanks
Answered by
15
Answer:
520 km/h,40 km/h
Step-by-step explanation:
Let’s assume the speed of the plane =x km/hr
And let the speed of wind =y km/hr
So, the speed of the aeroplane in the direction of wind =(x+y)km/hr
Speed of the aeroplane in the opposite direction of wind =(x–y)km/hr
We know that, distance=speed×time
Then according to the given conditions, we have
1680=(x−y)×3.5
⇒x−y=
3.5
1680
⇒x−y=480 … (i)
And,
1680=(x+y)×3
⇒x+y=
3
1680
⇒x+y=560 … (ii)
Adding equation (i) and (ii), we get
2x=1040
⇒x=
2
1040
=520
Substituting the value of x in equation (i), we get
520−y=480
⇒y=520−480
⇒y=40
Therefore, the speed of aeroplane =520 km/hr and the speed of wind =40 km/hr.
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