Question

An aeroplane flies 240km due north and then 320km due west .how many kilometers must it fly to return to its starting point by the shortest route.

Answer 1

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Answer 2

The total distance he has to travel to return to his starting point by the shortest route is 40 km.

• As the aeroplane flies due north and west the angle between west and north is 90°.
• The path travelled by the aeroplane starts from A and ends at C.
• The aeroplane travels 240 km north that is from A to B and 320 km west that is from B to C.
• Now we have to find the distance between A and C to compute the shortest route to return to its starting point.

Using Pythagoras Theorem,

AC² = AB² + BC²

AC² = 240² + 320²

AC² = 5760 + 10240

AC² = 160000

AC = 400 km

• The distance aeroplane needs to travel by the shortest distance is 400 km.