An aeroplane flies along sides of equilateral triangle with speeds 300km/hr,200km/hr,250km/hr . calculate its average speed
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(300+200+250)/3=750/3=250km/hr
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GIVEN; S1=300km/hr,S2=200km/hr,S3=250km/hr
TO FIND;
average speed(S)=?
SOLUTION;
Average speed(S)=(S1+S2+S3)÷3
S=(300+200+250)÷3
S=750÷3
S=250km/hr or S=250÷(5/18) m/s
S=(250×18)÷5
S=50×18
S=900m/s
THEREFORE,S=250km/hr Or 900m/s
THANK YOU!!!!!!!!!
TO FIND;
average speed(S)=?
SOLUTION;
Average speed(S)=(S1+S2+S3)÷3
S=(300+200+250)÷3
S=750÷3
S=250km/hr or S=250÷(5/18) m/s
S=(250×18)÷5
S=50×18
S=900m/s
THEREFORE,S=250km/hr Or 900m/s
THANK YOU!!!!!!!!!
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