An aeroplane flies along the sides of an equilateral triangle with speed of 300 km/hr, 200 km/hr, 240 km/hr. The average speed of the plane while flying around the triangle is:
a. 250 km/hr
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Answer:
Average speed = total distance covered\time taken
Let side of equilateral triangle = a km
Total distance covered = (a + a +a)km = 3a km
Time taken = sum of time taken by each side
= (a\300+a\300+a\300) hr
= 4a + 6a + 5a\1200 hr
= 15a\1200 hr
= a\80 hr
Hence, average speed = 3a\a\80
= 240 km/hr
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