Question

An aeroplane flying 490m above ground level at 100m/s, releases a block. how far on ground will it strike

Answer 1

this is solve by horizontal projectile
concept .
X=Ux.t+1/2.Ax.t^2

horizontal line acceleration of aeroplane is zero.

X=Ux.t-----------(1)

vertical line motion of aeroplane

Y=Uy.t+1/2Ay.t^2

in vertical acceleration is g but Uy =0

so , Y=1/2g.t^2 ----------(2)

now equation (1) and (2)

X=Ux.root (2Y/g)

=100root(980/9.8)=1000m