Question

An aeroplane flying at a height of 9000 m
from the ground passes vertically above
another aeroplane at an instant, when
the angles of elevation of the two planes
from the same point on the ground are
60° and 30° respectively. Find the
vertical distance between the
aeroplanes at that instant​

Answer 1

Answer:

Let the height of first plane be AB=4000m and the height of second plane be BC=xm

∠BDC=45

∘

and ∠ADB=60

∘

In △CBD

(i)

y

x

=tan45

∘

=1

⇒x=y

In △ABD,

y

4000

=tan60

∘

=

3

⇒x=y=

3

4000

3

=2306.67m

∴ the vertical distance between two=4000−y=4000−2306.67=1693.33m

solution