An aeroplane flying at height h with horizontal velocity u . The velocity of a dropped packet on reaching ground will be
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Explanation:the packet will have a velocity u as the initial horizontal velocity will not change as there is no force in that direction
U have mg force vertical anf by kinematic equation v = u in horizontal direction( which is zero)+ gt
=gt
Hence when it will reaxh ground its will have 2 component of velocity
Whose resultant will be √(u²+g²t²)
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