An aeroplane flying horizontally at an altitude of 490 m with a speed of 180 kmph drops a bomb. The horizontal distance at which it hits the ground is
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Explanation:
given,
speed of the airplane = 18 kph = 50 m/sec
it's altitude = 490 meter
1st of all we have to find out the time to travel 490 meter ,
now,
s = ut + 1/2 at²
490 = 0 * t + 1/2 * 9.8 * t²
490 = +4.9t²
490/4.9 = t²
100 = t²
10 = t
therefore time time taken to travel 490 meter = 10 sec
therefore now ,
horizontal distance = time taken * speed
distance = 10* 50
distance = 500 meter .
therefore the answer is 500 meter and the correct option is option(A) that is 500 m .
i hope it helps........................^_^
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