Question

an aeroplane flying horizontally with a speed of 360 km/h releases a bomb at a height of 490 m from the ground . if g= 10 m/s ^2 it will strike the ground at​

Answer 1

Answer:

ux=360 km/hr=360×518 m/s

⟹ux=100 m/s

(→+ve)

h=490 m

, height from which the bomb is dropped

Also, h=uyt + 12gt2  (↓+ve)

(uy=0)

& t = time taken by bomb to reach the ground

⟹t=2hg−−√

⟹t=2×490 m9.8 m/s2−−−−−−√

⟹t=10 s

x=ux×t=100 m/s×10 s

⟹x=1000 m=1 km

Explanation: