An aeroplane flying horizontally with a speed of 360 km/hr releases a bomb at a height of 490 m from the ground. It will strike the ground at
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Answer:
Time taken by the bomb to fall through a height of 490 m
t=
g
2h
=
9.8
2×490
=10s
The distance at which the bomb strikes the ground = horizontal velocity x time
=360kmh
−1
×10s
=360kmh
−1
×(
3600
10
)h=1km
Explanation:
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