Question

an aeroplane flying horizontally with a speed of 98m/s releases a bomb at a height of 980m. find the velocity with which it strikes the ground.

Answer 1

Given:

Speed = 98 m / s

Height = 980 m

To find:

Velocity

Solution:

According to the laws of motion,

Velocity^2 - initial velocity^2 = 2 * Gravity * height

Here,

Initial velocity = 0

Substituting,

We get,

velocity^2 = 2 * 9.8 * 980

Hence,

Velocity = 138.5 m / s