Question

An aeroplane flying horizontally with a velocity 600km/h at height 1960.When it is vertically at a point a on the ground, a bomb is realsed from it. The bomb strike the ground at b the distance ab is

Answer 1

Answer:

x=166.67(19.8)

x= 3300

Explanation:

First find the time using the y equation for projectile motion. The time is equal to 19.8 seconds, then substitute the time and the speed 600km/h into the x equation for projectile motion. Remember to change 600km/h into 166.67m/s before you substitute into the equation.

Answer 2

Answer:

mark me as brainliest and thank me if the answer is useful.

Explanation:

see in the question its given:

Velocity= 600Km/hr = 600x1000/3600 m/s=166.66m/s

Ht=1960m.

To Find: The range of the projectile (R).

Its actually a Projetile motion .

For a projectile Ht=1/2*g*t*t.There fore we get t= 20s.

R=V*t=166.66*20=3333.33m/s=3.333Km/hr.