Math, asked by seenu9838, 11 months ago

An aeroplane has 4 emergency exits.In an emergency it requires 8 seconds per passenger to evacuate the plane.If no hand baggage is carried by the passenger .How long will it take to evacuate 53 passengers in an emergency (when hand baggage is not allowed to be carried)? None of the other 3 choices?

Answers

Answered by royabhayraftar
0

Answer:

7849 hrs

because 4 emergency exist multiply by 8 seconds per passenger and carried the passengerksjsbdbbhshahajjajanssnssnsmsmskoaksnnndndndndmdmskkss shsjsmaaok sjssjsjjsjsii ==????

Step-by-step explanation:

Answered by mkursheed93
2

Answer:

given data :

4 emergency exits

53 passengers on board

requires 8 seconds per passenger to evacuate through one exit

Number of passengers evacuated for every 8 second = 4 (since 4 exits )

total time to evacuate all the passenger is

112 seconds

(104 seconds to evacuate 52 passengers through 4 exit and 8 sec for last passenger)

52÷4=13 passengers from each exit and last passenger alone

(13×8 =104 sec )+ 8 second=112 second

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