Question

An aeroplane has a run of 500 m to take
off from the runway. It starts from rest
and moves with constant acceleration to
cover the runway in 30 sec. What is the
velocity of the aeroplane at the take off ?​

Answer 1

$500 = 0 \times 30 + \frac{1}{2} a ({30})^{2}$

$500 = \frac{1}{2} a \times 900 \\ a = \frac{500 \times 2}{900} \\ a = \frac{10}{9} = 1.11 \: m {s}^{ - 2}$

$v = u + at \\ \: \: v = 0 + (1.11 \times 30) \\ v = 33.33 \: m {s}^{ - 1}$