Question

an aeroplane has a run of 500m to take off from the runway it starts from rest and moves with constant acceleration to cover the runway in 30 sec what is the velocity of the aeroplane at the take off​

Answer 1

Answer:

velocity of the aeroplane at the take off​ = 100/3 m/s

Explanation:

Using S = ut + (1/2)at²

S = 500 m

u = 0   Start from rest

a = ?

t = 30 sec

=> 500 = 0 + (1/2)a(30)²

=> a = 1000/900

=> a = 10/9  m/s²

V = u + at

=> V = 0 + (10/9) * 30

=> V = 100/3 m/s

velocity of the aeroplane at the take off​ = 100/3 m/s

Answer 2

Answer:

ans: 120 km/hr

Explanation:

solution:

s = it + 1/2 + at^2

s = 1/2 + at^2 ( u = 0 )

a = 2s/t

= 2×500/(30)^2

=1000/900

=10/9 m/s^2

v = u + at

= 10/3 × 30

= 300/9 m/s

300/9 × 3600/1000 km/hr

= 3×4

=120 km/hr

hope this helps you frds ☺